OK. 7 feet = 2.15 meters, so for 2% voltage drop, wire area = 7.722 mm^2, which is about 8 AWG. You can see here the obvious reduction in losses as wire length or circuit current decreases. AC is a bit of a different story, but this is essentially why your power utility steps up the voltage into hundreds of kilovolts for long distance power transmission.
-Sean
On Jan 15, 2009, kocpnt@tds.net wrote:
Hi Shawn,The maximum run of the main bus will be about 7 feet. They will split off into smaller loads at that time.Thanks,Jim K----- Original Message -----From: Sean T. StevensonSent: Thursday, January 15, 2009 11:21 AMSubject: Re: [PSUBS-MAILIST] Wire SizeJim, to answer this question, you also need to know the total length of the wire run.
The resistivity (rho) of any material is a temperature dependent variable, but the variance is small, and values for many materials at 20 degrees C are available on the internet. A quick search provides the resistivity value for copper as 1.724E-8 ohm*meters.
Resistance, resistivity, length and cross-sectional area are related by the equation
R = (rho * l )/A
Voltage, current and resistance are related by the equation
V=I*R
Combining the two, and rearranging for A gives
A = (I * rho * l ) / V
Now, it is important to note that the V above is not your nominal operating voltage, but rather a voltage corresponding to the acceptable voltage drop in the wire. Many electrical codes give this as around 2% of the nominal voltage, so for a 36V system that would be 0.72 V. You didn't provide a wire length, but for the purpose of discussion, for a 10 meter wire, you have
A = (150 * 1.724E-8 * 10) / 0.72 = 3.6E-5 m^2, or 36 mm^2. The corresponding AWG wire gauge is about 2 AWG.
This is large, but this would be necessary if you were running at full power continuously, and could not tolerate voltage drops higher than 0.72V. Provided you stay within safety limits (i.e. the isolation voltage limit of the wire insulation), and can tolerate more heat, and more voltage drop in the wire at maximum current, you can derate this to be a more appropriate fit to the expected continuous load.
-Sean
On Jan 15, 2009, kocpnt@tds.net wrote:
************************************************************************ ************************************************************************ ************************************************************************ The personal submersibles mailing list complies with the US Federal CAN-SPAM Act of 2003. Your email address appears in our database because either you, or someone you know, requested you receive messages from our organization. If you want to be removed from this mailing list simply click on the link below or send a blank email message to: removeme-personal_submersibles@psubs.org Removal of your email address from this mailing list occurs by an automated process and should be complete within five minutes of our server receiving your request. PSUBS.ORG PO Box 53 Weare, NH 03281 603-529-1100 ************************************************************************ ************************************************************************ ************************************************************************Hi All,I am looking for advice. I am looking for the proper size of copper wire to power my sub.This wire will go from the batteries and at maximum draw will need to handle about 150 amps total load at 36 volts DC. I realize that there places to look for this, but felt that the experienced people in the community might have some good insights!Thanks in advance,Jim K