[PSUBS-MAILIST] new submarine inside to outside hydraulic

[swaters]

Dan,
You are brilliant!
Thanks,
Scott Waters




Sent from my U.S. Cellular© Smartphone"Dan H." <jumachine at comcast.net> wrote:How to solve the problem of depth figuring in on the situation is to use 
double ended cylinders.  With a rod of the same size sticking out of each 
end of each cylinder the effect of water pressure balances out.  The force 
is the same in either direction.

Dan H.

----- Original Message ----- 
From: "hank pronk" <hanker_20032000 at yahoo.ca>
To: "Personal Submersibles General Discussion" 
<personal_submersibles at psubs.org>
Sent: Saturday, April 12, 2014 8:58 AM
Subject: Re: [PSUBS-MAILIST] new submarine inside to outside hydraulic


Hi Carsten,
I am not sure about your math, I get a much different figure.
A 1/2 in rod has an area of .19in
multiply by 1,000 foot depth salt water 445psi = 87.33 lbs
With a 10 to 1 lever that would be 8.7 lbs to push with your arm.
Also you want a smaller cylinder inside with a longer stroke and you get an 
even lighter load on your arm.
Hank

Subject: Re: [PSUBS-MAILIST] new submarine inside to outside hydraulic
To: "Personal Submersibles General Discussion" 
<personal_submersibles at psubs.org>
Received: Saturday, April 12, 2014, 2:56 AM





E-Mail Software 6.0

Hi Scott,

1 bar = 0,1
N/mm2

1000 meter depth = 100 bar or 10 N/mm2
(or 1
kg/mm2)

A Hydraulic stamp of a 1/2 inch has a surface of 126

mm2
means the outside waterpressure on the cylinder stamp is
1267
N or
127 Kg or 0,13 ts.

If you make a drawing of your schematic you
will see
that it is not selfcompensating.
Means you need a inside force of
that
amout just to compensate.
If you asume you can take a pressure
of 0,013
ts
with some comfore by hand you inside zylinder piston has to
be
the 10
times more diameter thn the outside one.

By the way the same
force works
on your troughulls cables of the same diameter.

vbr Carsten




<swaters at waters-ks.com> schrieb:

I have a question maybe someone can answer.
If you have two hydraulic cylinders that are completely
filled with
oil (no air pockets anywhere in the system) one in a
submarine and on
outside of a submarine. Each cylinder has the rod side
connected to the
head side of the other cylinder so when on rod extends, the
flow of one
makes the other cylinder do the same exact thing. Would the
one cylinder
that does the same as the other cylinder on the surface
function the
same way at depth? Or would the deeper you go the more force
you would
have trying to push the rod into the cylinder?

Thanks,
Scott Waters




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