Re: sub weight

["STEVE McColman" <steve_mccolman@hotmail.com>]

>From: Dick Morrisson <rmorrisson@unidial.com>
>Reply-To: personal_submersibles@psubs.org
>To: personal_submersibles@psubs.org
>Subject: Re: sub weight
>Date: Mon, 31 May 1999 12:34:52 -0700
>
>Steve,
>The formula for the volume of an oblate spheroid (an ellipse revolved about 
>its
>minor axis) is 4/3 times pi times a times b squared, where "a" is the 
>radius of
>the minor axis and "b" is the radius of the major axis and pi is ~3.14 .  
>For
>your example "a" would equal 7" and "b" would equal 15".  I believe this is 
>the
>correct formula for the volume but it hasn't stood up to the "fork" test 
>yet so
>double check it before going too far with your design.
>Dick

----------------------------------------------------
>
Im still a little confused,   I want to find out how many cubic feet of air 
is in my hatch.  My hatch is 24" Dia.  and 7"wide.  1.33 x 3.14 x .58 x 1 = 
2.42 cu/ft   Is that right???


Ends are 30" Dia.  and 7" wide.
My ends---- 1.33 x 3.14 x .58 x 1.56 = 3.8 cu/ft in EACH end ????


                                 Steve McColman, Vancouver Island


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