Re: [PSUBS-MAILIST] formula for leak volume?

[irox <irox@ix.netcom.com>]

Hi,

he's how I tackled the same question.  Definitely not ideal, but
probably good enough to get the idea.

(A)area of leak = (outer hole area) - (inner shaft area)
A = pi * .0127254^2 - pi * 0.127^2 
  = 0.00000203 m^2

(P)pressure = 500psi
  = 3447378pa

(q) Water density = 1000 Kg / meter^3 

(C) flow coefficient (guessing at 0.62, 1 would be frictionless)

(V) volume (GIECK Engineering formulas)
V = C * A * sqrt( 2 * P / q )

  = 0.62 * 0.00000203 * sqrt ( 2 * 3447378 / 1000 )

  = 0.000088055 m^3 per second

  = 0.088 liters per second
  = 5.28 liters per minute.

Please feel free to check my calcs.  If I've done something wrong,
I would very much like to know where.

Cheers,
  Ian.

-----Original Message-----
>From: "Smyth, Alec" <Alec.Smyth@compuware.com>
>Sent: Feb 5, 2009 8:43 PM
>To: personal_submersibles@psubs.org
>Subject: [PSUBS-MAILIST] formula for leak volume?
>
>I'm trying to calculate something but haven't found the right formula. Let's say the seal on my 1" prop shaft disintegrates. Just inboard of the seal, the shaft goes through an opening that is 1.002". This opening is not of any significant length The ambient pressure is 500 psi. How many gallons or liters per minute would come in?
> 
>I'd really appreciate any pointers!
> 
> 
>thanks,
>
>Alec
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