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Vertical speed : was [PSUBS-MAILIST] Re: Test and questions
Okay, unfortunatly the email programm has no formula maker..
so I have to descripe them as best as I can ..
Vertikal speed = Vvert (m/s)
Overweight/underweight = Fvert (N)
Desinty of water = ro for saltwater 1025 kg/m3
Water resistands of a horizontal cylinder
in vertikal direction with a l/d (length to diameter)= 10
= Cw = 0,82 (for metric units..)
Area (medium length x beam) = A (m x m = m2)
Formula:
Vvert = square roots of (( 2 x Fvert) divided by (ro x Cw x A))
1.) example :
CSSX beam = diameter of pressure hull = 2,5 m
CSSX length =
(length of pressure hull 10m and overall length is 16m)
medium length of area about = 13 m
A (vertical) about = 2,5 x 13 m = 32,5 m2
overweight/underweight of here regulator tank = here 50 kg or liter..
with 50 kg equal with 500 Newton (N)
so (2 x 500) / (1025 x 0,82 x 32,5 )
= 1000 / 27316
= 0,0366
the square root of that is 0,1913 m/sec vertical speed
or x 60 seconds = 11,48 m/min equal to 37,7 feet at one minute
table with over/underweights
25 kg = 8,2 m/min or 27 feet/minute (normal regulator action)
50 kg = 11,5 m/min or 38 feet/minute
100 kg = 16,4 m/min or 54 feet/minute (fast regulator action)
200 kg = 23,3 m/min or 76 feet/minute
9000 kg = 154,0 m/min or 500 feet/minute (full ballast blown from
greater deep)
13800kg = 190,7 m/min or 625 feet/minute (full b.blown and drop weight
f.g.d.)
seems will jump the hole boat out of the water...
2.) example - Sgt.Peppers emergency ballast blowing :
beam = 0,9 m
length about = 2,4 m
Ballast water = 90 liter = 900 N
A = 0,9 x 2,4 = 2,16 m2 (estimate)
density of freshwater = 1000 kg/m3
so (2 x 900) divided by (1000 x 0,82 x 2,16 )
= 1800 divided by 1771
= 1,016 m/sec
with 60 seconds
= 61 m/min (or with 1 feet = 0,3048 m) equal to 200 feet/min
and jumped out of the water like a young flipper :-)
look for "metric and units" in the archive to convert the
stuff into the old american way of live..
if you want to jump faster - make the ballast tanks greater and the
diameter
of the hull smaller..
see you flying, Carsten
"Michael B. Holt" schrieb:
>
> MerlinSub@t-online.de wrote:
> > Im have here a fornular to quick calculate the vertical speed of the
> > submarine
> > during raising or sinking. Ask if you want a quick calculation, its
> > needs beam
> > of the pressure hull, middle length of the sub (square area length)
> > and the over/under weight.
>
> Carsten, I'd like to see the formula. Thanks.
>
> Mike